Mean Deviation

How far, on average, all values are from the middle.

Calculating It

Find the mean of all values ... use it to work out distances ... then find the mean of those distances!

In three steps:

Like this:

Example: the Mean Deviation of 3, 6, 6, 7, 8, 11, 15, 16

Step 1: Find the mean:

Mean =  3 + 6 + 6 + 7 + 8 + 11 + 15 + 168  =  728  = 9

Step 2: Find the distance of each value from that mean:

Value Distance from 9
3 6
6 3
6 3
7 2
8 1
11 2
15 6
16 7

Which looks like this:

mean deviation

(No minus signs!)

Step 3. Find the mean of those distances:

Mean Deviation =  6 + 3 + 3 + 2 + 1 + 2 + 6 + 78  =  308  = 3.75

 

So, the mean = 9, and the mean deviation = 3.75

It tells us how far, on average, all values are from the middle.

In that example the values are, on average, 3.75 away from the middle.

For deviation just think distance

Formula

The formula is:

Mean Deviation = Σ|x − μ|N

Let's look at those in more detail:

absolute deviation

Absolute Deviation

Each distance we calculate is called an Absolute Deviation, because it is the Absolute Value of the deviation (how far from the mean).

To show "Absolute Value" we put "|" marks either side like this:

|−3| = 3

For any value x:

Absolute Deviation = |x − μ|

From our example, the value 16 has:

Absolute Deviation = |x − μ| = |16 − 9| = |7| = 7

And now let's add them all up ...

Sigma

The symbol for "Sum Up" is Σ (called Sigma Notation), so we have:

Sum of Absolute Deviations = Σ|x − μ|

Divide by how many values N and we have:

Mean Deviation = Σ|x − μ| N

 

Let's do our example again, using the proper symbols:

Example: the Mean Deviation of 3, 6, 6, 7, 8, 11, 15, 16

Step 1: Find the mean:

μ =  3 + 6 + 6 + 7 + 8 + 11 + 15 + 168  =  728  = 9

Step 2: Find the Absolute Deviations:

x |x  μ|
3 6
6 3
6 3
7 2
8 1
11 2
15 6
16 7
  Σ|x − μ| = 30

 

Step 3. Find the Mean Deviation:

Mean Deviation =  Σ|x − μ|N  =  308  = 3.75

Note: the mean deviation is sometimes called the Mean Absolute Deviation (MAD) because it is the mean of the absolute deviations.

What Does It "Mean" ?

Mean Deviation tells us how far, on average, all values are from the middle.

Here is an example (using the same data as on the Standard Deviation page):

Example: You and your friends have just measured the heights of your dogs (in millimeters):

statistics dogs graph

The heights (at the shoulders) are: 600mm, 470mm, 170mm, 430mm and 300mm.

 

Step 1: Find the mean:

μ =  600 + 470 + 170 + 430 + 3005  =  19705  = 394

Step 2: Find the Absolute Deviations:

x |x - μ|
600 206
470 76
170 224
430 36
300 94
  Σ|x − μ| = 636

 

Step 3. Find the Mean Deviation:

Mean Deviation =  Σ|x − μ|N  =  6365  = 127.2

 

So, on average, the dogs' heights are 127.2 mm from the mean.

(Compare that with the Standard Deviation of 147 mm)

A Useful Check

The deviations on one side of the mean should equal the deviations on the other side.

From our first example:

Example: 3, 6, 6, 7, 8, 11, 15, 16

The deviations are:

mean deviation

6 + 3 + 3 + 2 + 1   =   2 + 6 + 7
15   =   15

Likewise:

Example: Dogs

Deviations left of mean: 224 + 94 = 318

Deviations right of mean: 206 + 76 + 36 = 318

If they are not equal ... you may have made a msitake!

 

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